Question

calcule a soma dos infinitos termos termos da p.g.(9,3,1,...)

Answer 1

$Resolu\c{c}\~ao\to \left\{\begin{array}{ccc}P.G(9,3,1,...)\\\\a_1 = 9\\q = \frac{3}{9} = \frac{1}{3}\\\\Sn = \frac{a_1}{1-q}\\\\S_n = \frac{9}{ 1-\frac{1}{3} }\\\\S_n = \frac{9}{ \frac{3-1}{3} }\\\\S_n = \frac{9}{ \frac{2}{3} }\\\\\boxed{\boxed{S_n = 9* \frac{3}{2} = \frac{27}{2}}} \end{array}\right$

Espero ter ajudado. :))