Question

Calcule a soma dos 6 primeiros termos da p.g (3, 2, 4/3...)
Me ajudem!!

Answer 1

a1 = 3
a2 = 2
a3 = 4/3
q = 4/3: 2/1 = 4/3 * 1/2 = 4/6 = 2/3 ***
S6 =  3 [ ( 2/3)⁶ - 1 ]/ ( 2/3 - 1/1)
S6 = 3 [ (64/729) - 1/1 ] / ( -1/3)
S6 = 3 [ - 665/729 ]/ ( - 1/3)
S6 = 3 ( -665/729 ): ( - 1/3) 
S6 = 3 ( -665/729) * ( -3/1) 
S6 = 3 (- 1995/729 )
S6 = - 5985/729
S6 = - 665/81