Question

calcule a soma dos 53 termo da P.A onde A¹= 3 r=4​

Answer 1

$> resolucao \\ \\ \geqslant progressao \: aritmetica \\ \\ an = a1 + (n - 1)r \\ an = 3 + (53 - 1)4 \\ an = 3 + 52 \times 4 \\ an = 3 + 208 \\ an = 211 \\ \\ \\ = = = = = = = = = = = = = = = = = \\ \\ \\ \geqslant soma \: dos \: termos \: da \: pa \\ \\ \\ sn = \frac{(a1 + an)n}{2} \\ \\ sn = \frac{(3 + 211)53}{2} \\ \\ sn = \frac{214 \times 53}{2} \\ \\ sn = 107 \times 53 \\ \\ sn = 5671 \\ \\ > < > < > < > < >$