Question

calcule a soma dos 50 primeiros terrmos de P.A (2, 6,10)
pra agora!!!!!​

Answer 1

$> resolucao \\ \\ \geqslant progressao \: aritmetica \\ \\ r = a2 - a1 \\ r = 6 - 2 \\ r = 4 \\ \\ \\ an = a1 + (n - 1)r \\ an = 2 + (50 - 1)4 \\ an = 2 + 49 \times 4 \\ an = 2 + 196 \\ an = 198 \\ \\ \\ \geqslant soma \: dos \: termos \: da \: pa \: \\ \\ \\ sn = \frac{(a1 + an)n}{2} \\ \\ sn = \frac{(2 + 198)50}{2} \\ \\ sn = \frac{200 \times 50}{2} \\ \\ sn = 200 \times 25 \\ \\ sn = 5000 \\ \\ \\ > < > < > < > < > < > < >$