Question

calcule a soma das medidas dos angulos internos de um pentadecagono.

Answer 1

Si=(n-2)×180
Si=(15-2)×180
Si=13×180
Si=2340

Answer 2

$\sf S_i=(n-2)\cdot180^\circ$

$\sf S_i=(15-2)\cdot180^\circ$

$\sf S_i=13\cdot180^\circ$

$\red{\sf S_i=2340^\circ}$