Question

calcule a soma das medidas dos angulos internos de:

A) pentágono
B) heptagono

Answer 1

Vamos là:

formula:

Si = (n - 2)*180

a) pentágono

Si = (5 - 2)*180 = 540°

b) heptágono

Si = (7 - 2)*180 =  900°

Answer 2

A)

$\large \boxed{ \begin{array}{l} \rm \: S = (n - 2).180 {}^{ \circ} \\ \rm \: S = (5 - 2).180 {}^{ \circ} \\ \rm \:S = 3 \: . \: 180 {}^{ \circ} \\ \boxed{ \boxed{ \rm{S = 540 {}^{ \circ} }}}\end{array}}$

b)

$\large \boxed{ \begin{array}{l} \rm \: S = (n - 2).180 {}^{ \circ} \\ \rm \: S = (7 - 2).180 {}^{ \circ} \\ \rm \: S = 5 \: . \: 180 {}^{ \circ} \\ \boxed{ \boxed{ \rm{S = 900 {}^{ \circ} }}}\end{array}}$