Question

Calcule a seguinte integral indefinida ∫ (6x²+√x-3)dx:

Answer 1

Ficaria desse jeito:


∫ (6x² + √(x - 3) dx = ∫ 6x² dx + ∫ √(x - 3) dx

∫ 6x² dx = 6x³/3 = 2x³ 

∫ √(x - 3) dx = ∫ (x - 3)^(1/2) = (x - 3)^(3/2)/(3/2) 

∫ √(x - 3) dx = (2/3)*(x - 3)^(3/2)

∫ (6x² + √(x - 3) dx = 2x³ + (2/3)*(x - 3)^(3/2) + C