Matemática, perguntado por shaielimaciel, 6 meses atrás

Calcule a razão de cada uma das seguintes progressões geométricas:
a) (7,-7,7,-7...)
b)(32,16,8,4,...)
c)(9,27,81,...)
d)(81,27,9,3,...)​

Soluções para a tarefa

Respondido por niltonjunior20oss764
1

\boxed{a_n=a_kq^{n-k}}\ \therefore\ a_{n+1}=a_{n}q^{n+1-n}\ \therefore\ \boxed{q=\dfrac{a_{n+1}}{a_n}}

a)

(a_1,a_2,a_3,a_4,\dots)=(7,-7,7,-7,\dots)

q=\dfrac{a_2}{a_1}=\dfrac{-7}{7}\ \therefore\ \boxed{q=-1}

b)

(a_1,a_2,a_3,a_4,\dots)=(32,16,8,4,\dots)

q=\dfrac{a_2}{a_1}=\dfrac{16}{32}\ \therefore\ \boxed{q=\dfrac{1}{2}}

c)

(a_1,a_2,a_3,\dots)=(9.27,81,\dots)

q=\dfrac{a_2}{a_1}=\dfrac{27}{9}\ \therefore\ \boxed{q=3}

d)

(a_1,a_2,a_3,a_4,\dots)=(81,27,9,3,\dots)

q=\dfrac{a_2}{a_1}=\dfrac{27}{81}\ \therefore\ \boxed{q=\dfrac{1}{3}}


shaielimaciel: Muito obrigada!
Perguntas interessantes