Matemática, perguntado por shaielimaciel, 8 meses atrás

Calcule a razão de cada uma das seguintes progressões geométricas:

a) ( 7, -7, 7,-7, ...)



b) (32, 16, 8, 4, ...)



c) ( 9,27,81 ...)



d) (81, 27, 9, 3, ... )​

Soluções para a tarefa

Respondido por niltonjunior20oss764
0

\boxed{a_n=a_kq^{n-k}}\ \therefore\ a_{n+1}=a_{n}q^{n+1-n}\ \therefore\ \boxed{q=\dfrac{a_{n+1}}{a_n}}

a)

(a_1,a_2,a_3,a_4,\dots)=(7,-7,7,-7,\dots)

q=\dfrac{a_2}{a_1}=\dfrac{-7}{7}\ \therefore\ \boxed{q=-1}

b)

(a_1,a_2,a_3,a_4,\dots)=(32,16,8,4,\dots)

q=\dfrac{a_2}{a_1}=\dfrac{16}{32}\ \therefore\ \boxed{q=\dfrac{1}{2}}

c)

(a_1,a_2,a_3,\dots)=(9.27,81,\dots)

q=\dfrac{a_2}{a_1}=\dfrac{27}{9}\ \therefore\ \boxed{q=3}

d)

(a_1,a_2,a_3,a_4,\dots)=(81,27,9,3,\dots)

q=\dfrac{a_2}{a_1}=\dfrac{27}{81}\ \therefore\ \boxed{q=\dfrac{1}{3}}

Perguntas interessantes