Question

Calcule a raiz ou solução das equações do 1 grau com uma incógnita, sendo U = Q

Answer 1

a) $x-4-\frac{x+4}{3}=0$

$\frac{3x}{3}-\frac{12}{3}-\frac{x+4}{3}=0$

$\frac{3x-12-(x+4)}{3}=0$

$3x-12-(x+4)=0\cdot 3$

$3x-12-x-4=0$

$3x-x=12+4$

$2x=16$

$x=\frac{16}{2}$

$x=8$

b) $\frac{4x}{3}- \frac{3}{2}=\frac{x-3}{3}$

$\frac{8x}{6}-\frac{9}{6}=\frac{2x-6}{6}$

$\frac{8x-9}{6}=\frac{2x-6}{6}$

$8x-9=2x-6$

$8x-2x=-6+9$

$6x=3$

$x=\frac{3}{6}$

$x=\frac{1}{2}$

c) $\frac{3-x}{8}=\frac{x+1}{4}$

$\frac{3-x}{8}=\frac{2x+2}{8}$

$3-x=2x+2$

$-x-2x=2-3$

$-3x=-1$

$3x=1$

$x=\frac{1}{3}$

Answer 2

Explicação passo-a-passo:

a)x - 4 -(x +4)/3 = 0

3x - 12 = x + 4

3x - x = 4 + 12

2x = 16

x = 16/2

x = 8

b)

4x/3 - 3/2 = (x - 3)/3

8x - 9 = 2x - 6

8x - 9 = 2x - 6

8x - 2x = - 6 + 9

6x = 3

x = 3/6

x = 1/2

c)

(3 -x)/8 = (x + 1)/4

-x + 3 = 2x + 2

-x - 2x = 2 - 3

-3x = -1

3x = 1

x = 1/3