Question

calcule a medida dos ângulos internos do quadrilatero

Answer 1

$a+b=160\\3a=7b\\a=\frac{7b}{3}\\\frac{7b}{3}+b=160\\\frac{10b}{3}=160\\10b=160.3\\\\\boxed{b=48}\\\\\boxed{a=\frac{7.48}{3}=112}\\b-c=22\\48-c=22\\-c=22-48\\\\\boxed{c=26}\\\\a+b+c+d=360\\186+d=360\\\\\boxed{d=174}$

Answer 2

a+b=160

se 3a=7b
     a=7b/3

substituir
a+b=160
7b/3+b=160

mmc=3

7b+3b=480
10b=480
b=480÷10
b=48°

como a=7b/3
a=7(48)/3

a=112°

b-c=22
48-c=22
-c=22-48
-c=-26
c=26°

a+b+c+d=360°
112°+48°+26°+d=360°
186+d=360
d=360-186
d=174°