Question

Calcule a medida do complemento do ângulo que mede: 

a) 20°
b)15°30'
c)81°18'48''
d)67°45'
e)40°
f)80°
g)85°

Lembrando...Preciso dos cálculos. Pra quem responder corretamente receberá 30 pontos. Me ajudem, por favor !! eu acredito em vocês 

Answer 1

Ângulos complementares somam $90^{\circ}$.

a) $20^{\circ}$

$\alpha+20^{\circ}=90^{\circ}$

$\alpha=90^{\circ}-20^{\circ}$

$\alpha=70^{\circ}$


b) $15^{\circ}30'$

$\beta+15^{\circ}30'=90^{\circ}$

$\beta=90^{\circ}-15^{\circ}30'$

$90^{\circ}=89^{\circ}60'$:

$\beta=89^{\circ}60'-15^{\circ}30'$

$\bera=84^{\circ}30'$


c) $81^{\circ}18'48"$

$\gamma+81^{\circ}18'48"=90^{\circ}$

$\gamma=90^{\circ}-81^{\circ}18'48"$

$90^{\circ}=89^{\circ}59'60"$


$\gamma=89^{\circ}59'60"-81^{\circ}18'48"=8^{\circ}41'12"$


d) $67^{\circ}45'$

$\theta+67^{\circ}45'=90^{\circ}$

$\theta=90^{\circ}-67^{\circ}45'$

$90^{\circ}=89^{\circ}60'$

$\theta=89^{\circ}60'-67^{\circ}45'$

$\theta=22^{\circ}15'$


e) $40^{\circ}$

$\delta+40^{\circ}=90^{\circ}$

$\delta=90^{\circ}-40^{\circ}$


$\delta=50^{\circ}$


f) $80^{\circ}$

$80^{\circ}+\omega=90^{\circ}$

$\omega=90^{\circ}-80^{\circ}$

$\omega=10^{\circ}$


g) $85^{\circ}$

$85^{\circ}+\Omega=90^{\circ}$

$\Omega=90^{\circ}-85^{\circ}$

$\Omega=15^{\circ}$