Question

calcule a matriz x na equação matricial

Answer 1

Resposta:

$\textsf{Leia abaixo}$

Explicação passo a passo:

$\sf{(X - A)^t = B}$

$\sf{A = }\begin{bmatrix}\cancel1&\cancel2\\\cancel3&\cancel4\\\cancel5&\cancel6\end{bmatrix}$

$\sf{B = }\begin{bmatrix}\cancel0&\cancel -2&\cancel1\\\cancel1&\cancel4&\cancel5\end{bmatrix}$

$\sf{X = }\begin{bmatrix}\cancel \sf{x_{11}}&\cancel \sf{x_{21}}\\\cancel \sf{x_{21}}&\cancel \sf{x_{22}}\\\cancel \sf{x_{31}}&\cancel \sf{x_{32}}\end{bmatrix} - }\begin{bmatrix}\cancel1&\cancel2\\\cancel3&\cancel4\\\cancel5&\cancel6\end{bmatrix}$

$\begin{cases}\sf{x_{11} - a_{11} = b_{11} \:\:\: x_{11} - 1 = 0 \:\:\:\:\:\:x_{11} = 1}\\\sf{x_{12} - a_{12} = b_{21} \:\:\:x_{12} - 2 = 1 \:\:\:\:\:\:x_{12} = 3}\\\sf{x_{21} - a_{21} = b_{12} \:\:\:x_{21} - 3 = -2 \:\:\:x_{21} = 1}\\\sf{x_{22} - a_{22} = b_{22} \:\:\:x_{22} - 4 = 4 \:\:\:\:\:\:x_{22} = 8}\\\sf{x_{31} - a_{31} = b_{13} \:\:\:x_{31} - 5 = 1 \:\:\:\:\:\:x_{31} = 6}\\\sf{x_{32} - a_{32} = b_{23} \:\:\:x_{32} - 6 = 5 \:\:\:\:\:\:x_{32} = 11}\end{cases}$

$\sf{X = }\begin{bmatrix}\cancel \sf{1}&\cancel \sf{3}\\\cancel \sf{1}&\cancel \sf{8}\\\cancel \sf{6}&\cancel \sf{11}\end{bmatrix}$