Question

 Calcule
a massa molar do acido cítrico, C6H8O7, e de
MgCO3.

Answer 1

Oi Angello.

$C=12\\ H=1\\ O=16\\ \\ 12*6=72\\ 1*8=8\\ 7*16=112\\ \\ 72+8+122=192g/mol\\ \\ \\ Mg=1*24=24\\ C=1*12=12\\ O=3*16=48\\ \\ 24+12+48=84g/mol$