Question

Calcule a massa, em gramas, de 350 m3 de C4H10 nas CNTP. (c=12 h=1)
R: 906816,76g

Answer 1

Usando a Lei dos Gases Ideais:

$pV=nRT\Longrightarrow pV=\dfrac{m}{MM}RT.~\text{Como est\'a nas CNTP:}\\\\ \Longrightarrow 1\cdot350\cdot10^3=\dfrac{m}{4\cdot12+10\cdot1}\cdot0,082\cdot273\iff\\\\ 350\cdot10^3=\dfrac{m}{58}\cdot0,082\cdot273\iff m=\dfrac{58\cdot350\cdot10^3}{0,082\cdot273}\iff\\\\\boxed{m\approx906816,76~g}$