Question

Calcule a integral

Answer 1

$\int\limits^ \frac{1}{4} _0 {3e^{4y}} \, dy$


$3 \int\limits^ \frac{1}{4} _0 {e^{4y}} \, dy$


$3 *\frac{1}{4} *e^{4y} \left}\begin{array}{}\\& \end{array}\right]_0^ \frac{1}{4}$



$\frac{3}{4} *e^{4y} \left}\begin{array}{}\\& \end{array}\right]_0^ \frac{1}{4}$



$\frac{3}{4} *e^{ 4*\frac{1}{4} } - (\frac{3}{4} *e^{4*0})$



$\frac{3}{4} *e - (\frac{3}{4} *e^{0})$


$\frac{3}{4} *2,7182 - (\frac{3}{4} *1)$


$2,0387 - \frac{3}{4}$


$\boxed { \boxed {1,2887}}$

Answer 2

$\displaystyle\mathtt{\int\limits_{0}^{\frac{1}{4}}3{e}^{4y}dy} = \dfrac{3}{4}{e}^{4y\big|_{0}^{ \frac{1}{4}}} \\=\mathtt{ \frac{3}{4}( {e}^{4. \frac{1}{4}} - {e}^{4.0} )} = \frac{3}{4}(e - 1)$