Question

Calcule a integral:
∫ (2x^2 +12x+18)^6dx

Answer 1

Resposta:

∫ (2x^2 +12x+18)⁶   dx

∫ 2⁶*(x^2 +6x+9)⁶   dx

2⁶ ∫ [(x+3)²]⁶ dx

Fazendo u =x+3  ==> du =dx

2⁶ ∫ u¹² du

=2⁶ * u¹³/13   + c

=(64/13) * u¹³ + c

Sabemos que u=x+3

=(64/13) * (x+3)¹³ + c