Question

Calcule a equação x2-6x+2k-3=0

Answer 1

Resposta:

Explicação passo-a-passo:

x²-6x+(2k-3)=0

delta=36-8k+12=48-8k

x'=(6+V(48-8k))/2=

(6+V(4(12-2k))/2=(6+2V(12-2k)/2=3+V(12-2k)

x"=(6-V(48-8k))/2=

(6-2V(12-2k))/2=3-V(12-2k)

3+V(12-2k)-(3-V(12-2k)=2

2V(12-2k)=2

V(12-2k)=1

12-2k=1

-2k=-11

k=5,5