calcule a e boa para que os números 4,6 e 12 sejam inversamente proporcionais a 9 , a e b, nessa ordem
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4/ ( 1/9 ) = 6/ ( 1/a) = 12/ ( 1/b)
(4/1) : ( 1/9) = ( 6/1 ) : ( 1/a)
( 4/1) * ( 9/1) = ( 6/1 ) * ( a/1)
36 = 6a
a = 36/6 = 6 ****
( 4/1) : ( 1/9 ) = ( 12/1) : ( 1/b)
( 4/1 * (9/1) = ( 12/1 ) * ( b/1)
36 = 12b
b = 36/12 = 3 ****
(4/1) : ( 1/9) = ( 6/1 ) : ( 1/a)
( 4/1) * ( 9/1) = ( 6/1 ) * ( a/1)
36 = 6a
a = 36/6 = 6 ****
( 4/1) : ( 1/9 ) = ( 12/1) : ( 1/b)
( 4/1 * (9/1) = ( 12/1 ) * ( b/1)
36 = 12b
b = 36/12 = 3 ****
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