Question

calcule a distancia entre os pontos
a) A(3,9) e C(-7,0)
b)D(1/2,-1) e M(4,-6)

Answer 1

$a)d_{AC}=\sqrt{(3-(-7))^2+(9-0)^2}=\sqrt{(3+7)^2+9^2}= \\ \sqrt{10^2+9^2}=\sqrt{100+81}=\sqrt{181}$

$b)d_{DM}=\sqrt{(4-\frac{1}{2})^2+(-6-(-1)^2}=\sqrt{(\frac{7}{2})^2+(-6+1)^2}= \\ \sqrt{\frac{49}{4}+25}=\frac{\sqrt{149}}{4}$