Question

calcule a distancia entre os ponto A (3-1) e B (3,5)

Answer 1

$a~(3,-1)~~e~~b~(3,5)\\\\D_{ab} = \sqrt{(x_b-x_a)^2+(y_b-y_a)^2} \\\\\\ D_{ab} = \sqrt{(3-3)^2+(5-(-1))^2} \to \\\\ D_{ab} = \sqrt{0^2+(5+1)^2} \to \\\\ D_{ab} = \sqrt{0^2+6^2} \to \\\\ D_{ab} = \sqrt{0+36} \to \\\\ D_{ab} = \sqrt{36} \to \\\\ \large\boxed{ D_{ab} = 6}$

Answer 2

✅Após resolver os cálculos, concluímos que o valor da distância entre os referidos pontos é:

  $\Large\displaystyle\text{ \begin{gathered}\boxed{\boxed{\:\:\:\bf d(A, B) = 6\:u.\:c.\:\:\:}}\end{gathered} }$

Sejam os pontos:

                 $\Large\begin{cases} A(3, -1)\\B(3, 5)\end{cases}$

Para calcular a distância entre os referidos pontos fazemos:

  $\Large\displaystyle\text{ \begin{gathered} d(A, B) = \sqrt{(X_{B} - X_{A})^{2} + (Y_{B} - Y_{A})^{2}}\end{gathered} }$

                    $\Large\displaystyle\text{ \begin{gathered} = \sqrt{(3 - 3)^{2} + (5 - (-1))^{2}}\end{gathered} }$

                    $\Large\displaystyle\text{ \begin{gathered} = \sqrt{0^{2} + (5 + 1)^{2}}\end{gathered} }$

                    $\Large\displaystyle\text{ \begin{gathered} = \sqrt{0^{2} + 6^{2}}\end{gathered} }$

                    $\Large\displaystyle\begin{gathered} = \sqrt{36}\end{gathered}$

                    $\Large\displaystyle\begin{gathered} = 6\end{gathered}$

✅ Portanto, a distância é:

   $\Large\displaystyle\begin{gathered} d(A, B) = 6\:u.\:c.\end{gathered}$

$\LARGE\displaystyle\text{ \begin{gathered} \underline{\boxed{\boldsymbol{\:\:\:Bons \:estudos!!\:\:\:Boa\: sorte!!\:\:\:}}}\end{gathered} }$

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$\Large\displaystyle\text{ \begin{gathered} \underline{\boxed{\boldsymbol{\:\:\:Observe \:o\:Gr\acute{a}fico!!\:\:\:}}}\end{gathered} }$