calcule a distância entre os pares de pontos
Soluções para a tarefa
Resposta:
Para calcularmos a distnâncias entre dois pontos no plano cartesiano utilizamos d=\sqrt{(Xa-Xb)^2+(Ya-Yb)^2}d=(Xa−Xb)2+(Ya−Yb)2
A) ( 2,3) e (2,5)
\begin{gathered}d=\sqrt{(2-2)^2+(3-5)^2} \\ d=\sqrt{(-2)^2} \\ d=\sqrt{4} \\ d=2\end{gathered}d=(2−2)2+(3−5)2d=(−2)2d=4d=2
B) (0,6) e ( 1, 5)
\begin{gathered}d=\sqrt{(0-1)^2+(6-5)^2} \\ d=\sqrt{(-1)^2+1^2}\\d=\sqrt{1+1} \\ d=\sqrt{2}\end{gathered}d=(0−1)2+(6−5)2d=(−1)2+12d=1+1d=2
C) (2, 1) e ( -2, 4)
\begin{gathered}d=\sqrt{[2-(-2)]^2+(1-4)^2} \\ d=\sqrt{(2+2)^2+(-3)^2} \\ d=\sqrt{4^2+(-3)^2}\\d=\sqrt{16+9}\\d=\sqrt{25}\\d=5\end{gathered}d=[2−(−2)]2+(1−4)2d=(2+2)2+(−3)2d=42+(−3)2d=16+9d=25d=5
D) ( 6 ,3) e ( 2, 7)
\begin{gathered}d=\sqrt{(6-2)^2+(3-7)^2} \\ d=\sqrt{4^2+(-4)^2 \\ }\\d=\sqrt{16+16}\\d=\sqrt{32}\\d=4\sqrt{2}\end{gathered}
Caso ajude, dê 5 estrelas
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