Question

calcule a diagonal, a área total e volume de um cubo cuja soma das medidas das arestas e igual a 48 cm

Answer 1

Um cubo tem 12 arestas

$12a=48\\\\ a=\frac{48}{12}\\\\ \boxed{a=4\ cm}$

Diagonal

$D=a\sqrt{3}\\\\ \boxed{D=4\sqrt{3}\ cm}$

Área total

$A_t=6a^2\\\\ A_t=6*4^2\\\\ A_t=6*16\\\\ \boxed{A_t=96\ cm^2}$

Volume

$V=a^3\\\\ V=4^3\\\\ \boxed{V=64\ cm^3}$