Question

calcule a derivada:
y = (-3x + 8x + 1)/ (x^2 + x)^2

Answer 1

$y= \frac{-3x+8x+1}{ ( x^{2}+x)^{2} } \\ y= \frac{5x+1}{ ( x^{2}+x)^{2} } \\ y'=5x. \frac{1}{( x^{2} +x)^{2} }+(-2)( x^{2}+x )^{-3}.2x.(5x+1) \\ y'= \frac{5x}{( x^{2}+x)^{2} }+ \frac{12x(5x+1)}{( x^{2}+x)^{3} }$