Question

calcule a derivada de funçao:
1.
$y( \times ) = \frac{1}{4x { }^{2} - 3}$


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Answer 1

Resposta:

Explicação passo-a-passo:

Usando a regra do quociente

$(\dfrac{x}{y})'=\dfrac{x'.y-x.y'}{y^{2}}\\\\\\y'(x)=\dfrac{0.(4x^{2}-3)-1.8x}{(4x^{2}-3)^{2}}\\\\\\y'(x)=\dfrac{-8x}{(4x^{2}-3)^{2}}\\\\ou\\\\\\y'(x)=\dfrac{-8x}{16x^{4}-24x^{2}+9}$