Matemática, perguntado por danieljotan, 1 ano atrás

calcule a derivada de 6.tg^2(5x-1) , alguem me ajuda nessa por favor

Soluções para a tarefa

Respondido por andresccp
1
tabela de derivadas:
\bmatrix (u^{N})'=N*u^{N-1}*u'\\\\tg(u)'= sec^2(u)*u'  \end

aplicando isso
f(x)=6*tg^2(5x-1)\\\\\text{reescrevendo}\\\\f(x)=6*[tg(5x-1)]^2\\\\ \text{derivando}\\\\ f'(x)= 6*2*[tg(5x-1)]^{2-1} * [tg(5x-1)]'\\\\f'(x)=12*tg(5x-1)*[tg(5x-1)]'\\\\f'(x)=12*tg(5x-1)*sec^2(5x-1)*(5x-1)'\\\\f'(x)=12*tg(5x-1)*sec^2(5x-1)*(5-0)\\\\\boxed{\boxed{f'(x)= 60*tg(5x-1)*sec^2(5x-1)}}
Perguntas interessantes