Question

Calcule a area e o perimetro do retangulo a seguir raíz de 27 e raíz de 12

Answer 1

Resposta:

$\'area =\sqrt{27} \times\sqrt{12} \\ \\ \'area=\sqrt{27\times12} \\ \\ \'area=\sqrt{324 } \\ \\ \'area=\sqrt{2^2.3^2.3^2} \\ \\ \'area=2.3.3\\ \\ \'area=18$

Perímetro

$\sqrt{27} +\sqrt{12} +\sqrt{27} +\sqrt{12} =\\ \\ \sqrt{3^2.3} +\sqrt{2^2.3} +\sqrt{3^2.3} +\sqrt{2^2.3} =\\ \\ 3\sqrt{3} +2\sqrt{3} +3\sqrt{3} +2\sqrt{3} =\\ \\ (3+2+3+2)\sqrt{3} =\\ \\P= 10\sqrt{3}$