Question

Calcule a área dos retângulos abaixo:

Answer 1

A)$\sqrt[3]{10}* \sqrt{10} = 10^{ \frac{1}{3} }* 10^{ \frac{1}{2} }= 10^{ \frac{1}{3} + \frac{1}{2} } = 10^{ \frac{2+3}{6} } = 10^{ \frac{5}{6} } = \sqrt[6]{ 10^{5} }m^2$

B)$\sqrt[5]{64} * \sqrt[5]{64^2}= \sqrt[5]{32*2}* \sqrt[5]{32^2*2^2}= 2\sqrt[5]{2}* 4\sqrt[5]{4} = 8\sqrt[5]{8}m^2$