Question

Calcule a área do triângulo de vértices nos pontos: b) A(1,2), B(3, 3) e C(0, 5).

Answer 1

Resposta:

3,5 u.a

Explicação passo-a-passo:

A(1,2), B(3, 3) e C(0, 5)

(1 2 1)(1 2)

(3 3 1)(3 3)

(0 5 1)(0 5)

D=3+0+15-(0+5+6)

D=3+15-(11)

D=18-11

D=7

A= 1/2.| D|

A=1/2.| 7 |

A=1/2.(7)

A=7/2

A=3,5 u.a

Answer 2

$M=\begin{vmatrix}1&2&1\\3&3&1\\0&5&1\end{vmatrix}$

$det\,M=1(3-5)-2(3-0)+1(15-0)=-2-6+15\\A=15-8=7$

$A=\dfrac{1}{2}. |det\,M|=\dfrac{1}{2}.7$

$\boxed{\boxed{\mathsf{A=3,5\,u.a}}}$