Question

calcule A(aij)2×2=3.i+5.j​

Answer 1

Resposta:

$\textsf{Leia abaixo}$

Explicação passo a passo:

$\mathsf{A(aij)_{2\times2}=3i+5j}$

$\mathsf{A = }\begin{bmatrix}\cancel a_{11}&\cancel a_{12\\\cancel a_{21}&\cancel a_{22}\end{bmatrix}$

$\mathsf{A = }\begin{bmatrix}\cancel \mathsf{3.1 + 5.1}&\cancel \mathsf{3.1 + 5.2}\\\cancel \mathsf{3.2 + 5.1}&\cancel \mathsf{3.2 + 5.2}\end{bmatrix}$

$\mathsf{A = }\begin{bmatrix}\cancel \mathsf{3 + 5}&\cancel \mathsf{3 + 10}\\\cancel \mathsf{6 + 5}&\cancel \mathsf{6 + 10}\end{bmatrix}$

$\mathsf{A = }\begin{bmatrix}\cancel \mathsf{8}&\cancel \mathsf{13}\\\cancel \mathsf{11}&\cancel \mathsf{16}\end{bmatrix}$

Answer 2

✅ Tendo resolvido os cálculos, concluímos que a matriz quadrada de ordem 2 procurada é:

   $\Large\displaystyle\text{ \begin{gathered}\boxed{\boxed{\:\:\:\bf A = \begin{pmatrix} 8 & 13\\11 & 16\end{pmatrix}\:\:\:}}\end{gathered} }$

Seja a matriz:

       $\Large\displaystyle\begin{gathered} A_{(ij)}_{2\times 2} = 3i + 5j\end{gathered}$

Então, temos:

        $\Large\displaystyle\begin{gathered} A = \begin{pmatrix} a_{11} & a_{12}\\a_{21} & a_ {22}\end{pmatrix}\end{gathered}$

             $\Large\displaystyle\begin{gathered} = \begin{pmatrix}3\cdot1 + 5\cdot1 & 3\cdot1 + 5\cdot2\\ 3\cdot2 + 5\cdot1 & 3\cdot2 + 5\cdot2 \end{pmatrix} \end{gathered}$

             $\Large\displaystyle\begin{gathered} = \begin{pmatrix} 3 + 5 & 3 + 10\\6 + 5 & 6 + 10\end{pmatrix}\end{gathered}$

             $\Large\displaystyle\begin{gathered} = \begin{pmatrix} 8 & 13\\11 & 16\end{pmatrix} \end{gathered}$

✅ Portanto, a matriz é:

        $\Large\displaystyle\begin{gathered} A = \begin{pmatrix} 8 & 13\\11 & 16\end{pmatrix} \end{gathered}$

$\LARGE\displaystyle\text{ \begin{gathered} \underline{\boxed{\boldsymbol{\:\:\:Bons \:estudos!!\:\:\:Boa\: sorte!!\:\:\:}}}\end{gathered} }$

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