Question

calcule:
a) A=(3/4)^2•(-2)^3+(-1/2)^1
b) B=(1/2)^-2+(-1/3)^-1
c) C=-2•(3/2)^3+1^15-(-2)^1
d) D=[(-5/3)^-1+(5/2)^-1]^-1

MIM AJUDEM PFVVVV​

Answer 1

Resposta:

a) A=(3/4)^2.(-2)^3+(-1/2)^1 b)

9/16.-8-1/2=

- 72/16 -1/2=. mmc(16)

-72-8/16=

-80/16= -5

B=(1/2)^-2+(1/3)^-1

(2)^2+(3)^1=

4+3=7

c) C=-2.(3/2)^3+1^15-(-2)^1

2.27/8+1+2

48/8+3 mmc(8)

48+24/8=

72/8=9

d) D=[(-5/3)^-1+(5/2)^-1]^-1

[-3/5+2/5]^-1

[-1/5]^-1=

-5^1= -5

e) E=[3^-1-(-3)^-1]^-1

1/3-1/3-1= -1

f) F=6.(2/3)^2+4.(-3/2)^-2

6.(4/9+4.(-2/3)^2

6.4/9+4.4/9

24/9+16/9=

40/9

Explicação passo a passo:

:)