Question

Calcule A)9(10+2)=
B)9(2+5)-10(6-2)=
C)54:(9x3-3x3)+3x1=
D)6(42:7-4)-0:3=
E)(4x8:2):8+2x5=
F)256:(32:2:2:2):4=
G)[15+2(3+4)]=
H)[45-(3x5-2)]:8=
I)6[(36:9-3)x(8:2)]:3=
J)6x8+[48:12-48:(4+12)]=
K)48-2[125:5(8-36:6)]:2=
Me ajudem!!!!!

Answer 1

a) 9*(10+2) = 9*12 = 108

b) 9*(2+5) - 10*(6-2)

9*7 - 10*4

63-40 = 103

c) 54:(27-9) + 3

54:18+3

3+3=6

d) 6*(6-4)-0

6*2-0

12-0 = 2

e) (4*4):8+2*5

16:8+10

2+10 = 12

f) 256:4:4

64:4 = 16

g) [15+2*7]

15+14 = 29

h) [45-(15-2)]:8

[45-13]:8

32:8 = 4

i) 6*[(36:9-3)*(8:2)]:3

6*[(4-3)*4]:3

6*[1*4]:3

6*4:3

24:3 =8

j) 6*8+[48:12-48:(4+12)]

6*8+[4-48:16]

6*8+[4-3]

6*8+1

48+1=49

k) 48-2[125:5*(8-6)]:2

48-2*[25*2]:2

48-2*50:2

48-2*25

46*25= 1 150

Espero ter ajudado