Question

Calcule :

a) 4⁻² =
b) 4⁻³ =
c) 5⁻¹ =
d) 3⁻³ =
e) 10⁻² =
f) (-5)⁻² =
g) (-3)⁻⁴ =
h (-2)⁻⁵ =
i) (-5)⁻³ =
j) (3/7)⁻² =
k) (2/5)⁻¹ =
l) (-5/4)⁻³ =
m) (-1/3)⁻² =
n) (-2/5)⁻³ =

Answer 1

Explicação passo-a-passo:

B)

$4 {}^{ - 3 = \frac{1}{4 {}^{3} } } \\ 4 {}^{3} = 4 \times 4 \times 4 = 64 \\ \frac{1}{64}$

A)

$4 {}^{ - 2} = \frac{1}{4 {}^{2} } \\ 4 {}^{2} = 4 \times 4 = 16 \\ \frac{1}{16}$

C)

$5 {}^{ - 1} = \frac{1}{5} \\ qualquer \: expressao \: elevada \: a \: potencia \: - 1 \: \\ resulta \: no \: seu \: inverso$

D)

$3 {}^{ - 3} = \frac{1}{3 {}^{3} } \\ 3 {}^{3} = 3 \times 3 \times 3 = 27 \\ \frac{1}{27}$

E)

$10 {}^{ - 2} = \frac{1}{10 {}^{2} } \\ 10 {}^{2} = 10 \times 10 = 100 \\ \frac{1}{100}$

F)

$( - 5) {}^{ - 2} = 5 {}^{ - 2} \\ \frac{1}{5 {}^{2} } \\ 5 {}^{2} = 5 \times 5 = 25 \\ \frac{1}{25}$

G)

$( - 3) {}^{ - 4} = 3 {}^{ - 4} \\ \frac{1}{3 {}^{4} } \\ 3 {}^{4} = 3 \times 3 \times 3 \times 3 = 81 \\ \frac{1}{81}$

H)

$( - 2) {}^{ - 5} = - 2 {}^{ - 5} \\ - \frac{1}{2 {}^{5} } \\ 2 {}^{5} = 2 \times 2 \times 2 \times 2 \times 2 = 32 \\ - \frac{1}{32}$

I)

$( - 5) {}^{ - 3 } = - 5 {}^{ - 3} \\ - \frac{1}{5 {}^{3} } \\ 5 {}^{3} = 5 \times 5 \times 5 = 125 \\ - \frac{1}{125}$

J)

$( \frac{3}{7}) {}^{2} = ( \frac{7}{3}) {}^{2} \\ \frac{7 {}^{2} }{3 {}^{2} } = \frac{49}{3 {}^{2} } = \frac{49}{9}$

K)

$( \frac{2}{5}) {}^{ - 1} = \frac{5}{2}$

L)

$( \frac{ - 5}{4}) {}^{ - 3} = ( \frac{4}{ - 5}) {}^{3} \\ ( \frac{4}{5}) {}^{3} = \frac{4 {}^{ 3} }{( - 5) {}^{3} } = \frac{64}{( - 5) {}^{3} } = \frac{64}{ - 125 } \\ - \frac{64}{125}$

M)

$( \frac{ - 1}{3}) {}^{ - 2} = ( \frac{3}{ - 1}) {}^{2} \\ ( - 3) {}^{2} = 3 {}^{2} = 3 \times 3 = 9$

N)

$( \frac{ - 2}{5}) {}^{ - 3} = ( \frac{5}{ - 2}) {}^{3} \\ ( \frac{5}{ - 2}) {}^{ - 3} = \frac{5 {}^{3} }{( - 2) {}^{3} } = \frac{125}{( - 2) {}^{3} } = \frac{125}{ - 8} \\ - \frac{125}{8}$