Question

Calcule
a) 4!_-_2!_-0!_.
3!

b) 12!_
9!

Answer 1

a) 4! = 4*3*2*1 = 24

3! = 3*2*1 = 6

2! = 2*1 = 2

0! = 1

$\frac{4! - 2! - 0! }{3! } = \frac{24 - 2 - 1}{6} = \frac{21}{6} = 3,5$

b) $\frac{12!}{9!} = \frac{479 001 600}{362 880} = 1 320$