Calcule
A- ⁴√1
B- ⁵√-32
C- ⁵√243
Soluções para a tarefa
Respondido por
2
Vamos lá :
![\sqrt[4]{1} = 1 ~~~, pois ~~1.1.1.1 = 1^4 = 1](https://tex.z-dn.net/?f=+%5Csqrt%5B4%5D%7B1%7D+%3D+1+%7E%7E%7E%2C+pois+%7E%7E1.1.1.1+%3D+1%5E4+%3D+1+ "\sqrt[4]{1} = 1 ~~~, pois ~~1.1.1.1 = 1^4 = 1")
![\sqrt[5]{-32} = \sqrt[5]{-32} \\ \\ 32|2 \\ 16|2 \\ 08|2 \\ 04|2
\\ 02|2 \\ 01~~~~~~~==\ \textgreater \ 2*2*2*2*2 = 2^5 \\ \\ =
\sqrt[5]{-2^5} = - 2](https://tex.z-dn.net/?f=%0A+%5Csqrt%5B5%5D%7B-32%7D++%3D++%5Csqrt%5B5%5D%7B-32%7D++++%5C%5C++%5C%5C+32%7C2+%5C%5C+16%7C2+%5C%5C+08%7C2+%5C%5C+04%7C2+%0A%5C%5C+02%7C2+%5C%5C+01%7E%7E%7E%7E%7E%7E%7E%3D%3D%5C+%5Ctextgreater+%5C+2%2A2%2A2%2A2%2A2+%3D+2%5E5+%5C%5C++%5C%5C++%3D++%0A%5Csqrt%5B5%5D%7B-2%5E5%7D++%3D+-+2 "\sqrt[5]{-32} = \sqrt[5]{-32} \\ \\ 32|2 \\ 16|2 \\ 08|2 \\ 04|2
\\ 02|2 \\ 01~~~~~~~==\ \textgreater \ 2*2*2*2*2 = 2^5 \\ \\ =
\sqrt[5]{-2^5} = - 2")
![\sqrt[5]{243} \\ \\ 243 |3 \\
081|3 \\ 027|3 \\ 009|3 \\ 003|3 \\ 001 ~~~~~~==\ \textgreater \
3*3*3*3*3 = 3^5 \\ \\ \sqrt[5]{243} = \sqrt[5]{3^5} = 3](https://tex.z-dn.net/?f=+%5Csqrt%5B5%5D%7B243%7D++%5C%5C++%5C%5C+243+%7C3+%5C%5C%0A+081%7C3+%5C%5C+027%7C3+%5C%5C+009%7C3+%5C%5C+003%7C3+%5C%5C+001+%7E%7E%7E%7E%7E%7E%3D%3D%5C+%5Ctextgreater+%5C++%0A3%2A3%2A3%2A3%2A3+%3D+3%5E5+%5C%5C++%5C%5C++%5Csqrt%5B5%5D%7B243%7D+%3D+%5Csqrt%5B5%5D%7B3%5E5%7D+%3D+3+ "\sqrt[5]{243} \\ \\ 243 |3 \\
081|3 \\ 027|3 \\ 009|3 \\ 003|3 \\ 001 ~~~~~~==\ \textgreater \
3*3*3*3*3 = 3^5 \\ \\ \sqrt[5]{243} = \sqrt[5]{3^5} = 3")
Espero ter ajudado !!
Espero ter ajudado !!
jessicadesconh:
NAO ENTENDI NADA '-'
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