Question

Calcule:

a) ( + 3x²)² =
b) (-8x⁴)² =
c) (2x⁵)³ =
d) (3y²)³ =

me ajuda aii .​

Answer 1

Explicação passo-a-passo:

a) ( + 3x²)² =

$\left(3x^2\right)^2=0$

b) (-8x⁴)² =

$\left(-8x^4\right)^2=0$

c) (2x⁵)³ =

$=2^3\left(x^5\right)^3\\\\=8\left(x^5\right)^3\\\\=8x^{5\cdot \:3}\\\\=8x^{15}$

d) (3y²)³ =

$=\left(3y^2\right)^3\\\=3^3\left(y^2\right)^3\\\=27y^{2\cdot \:3}\\\=27y^6$