Question

calcule:
a)3x +6=16-2x

b)-19x + 64=82-23x

c)32x + 25=14+9+40x

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Answer 1

Explicação passo-a-passo:

a)

3x+6=16-2x

3x+2x = 16-6

5x= 10

$x = \frac{10}{5}$

x=2

b)

-19x+64=82-23x

-19x+23x= 82 -64

4x= 18

$x = \frac{18}{4}$

x=

$\frac{9}{2}$

c)

32x+25= 14+9+40x

32x-40x= 23-25

-8x= -3 (-1)

8x= 3

$x = \frac{3}{8}$

Answer 2

Explicação passo-a-passo:

A)

3x + 6 = 16 - 2x

3x + 2x = 16 - 6

5x = 10

x = 10 ÷ 5

x = 2

B)

- 19x + 64 = 82 - 23x

- 19x + 23 = 82 - 64

4x = 18

x = 18/4 :2

x = 9/2

C)

32x + 25 = 14 + 9 + 40x

32x - 40x = 14 + 9 - 25

- 8x = - 2

x = - 2 ÷ - 8

x = 2/8 :2

x = 1/4