Matemática, perguntado por SenhoritaAnonima, 1 ano atrás

Calcule:

A)35º 29' 13" + 85º 40" =

B)30º 20' 15" + 19º 43' 50" =

C)70º - 15º 20' =

D)54º 40' 30" - 14º 15' 45" =

E)( 3º 20' 30" ) . 2 =

F)( 37º 18' ) : 3 =

Soluções para a tarefa

Respondido por Usuário anônimo
2
Boa tarde!

a)
35^{\circ}\;29'\;13''+85^{\circ}\;40''\\\\=\overbrace{120^{\circ}}^{35^{\circ}+85^{\circ}}\;29'\;\overbrace{53''}^{13''+40''}\\\\=\boxed{120^{\circ}\;29'\;53''}

b)
30^{\circ}\;20'\;15''+19^{\circ}\;43'\;50''\\\\=\overbrace{49^{\circ}}^{30^{\circ}+19^{\circ}}\;\overbrace{63'}^{20'+43'}\;\overbrace{65''}^{15''+50''}\\\\=\overbrace{50^{\circ}}^{49^{\circ}+1^{\circ}}\;\overbrace{4'}^{63'+1'-60'}\;\overbrace{9''}^{69''-60''}\\\\=\boxed{50^{\circ}\;4'\;9''}

c)
70^{\circ}\;-15^{\circ}\;20'\\\\=\overbrace{69^{\circ}}^{70^{\circ}-1^{\circ}}\;60'-15^{\circ}\;20'\\\\=\overbrace{54^{\circ}}^{69^{\circ}-15^{\circ}}\;\overbrace{40'}^{60'-20'}\\\\=\boxed{54^{\circ}\;40'}

d)
54^{\circ}\;40'\;30''-14^{\circ}\;15'\;45''\\\\=54^{\circ}\;39'\;90''-14^{\circ}\;15'\;45''\\\\=\boxed{40^{\circ}\;24'\;45''}

e)
\left(3^{\circ}\;20'\;30''\right)\cdot 2\\\\=6^{\circ}\;40'60''\\\\=\boxed{6^{\circ}\;41'}

f)
\left(37^{\circ}\;18'\right):3\\\\=\left(\overbrace{36^{\circ}}^{37^{\circ}-1^{\circ}}\;\overbrace{78'}^{18'+60'}\right):3\\\\=\boxed{12^{\circ}\;26'}

Espero ter ajudado!
Perguntas interessantes