Question

calcule A(3+√64) B( 2+3√2) C(4√3-1) D(√16+√1/9-√1/4) E(3*8+1) F(-√100)

Answer 1

a
3  + V64  = 3 + 8 = 11***
b
2 + 3V2 = 2 + 3 .1.41 = 2 + 4.23 = 6,23 ***
c
4V3 - 1 = 4. 1,73  - 1 = 6.92 - 1 = 5.92***
d
V16 + V1/9 - V1/4 = 4/1 + 1/3 - 1/2 =  ( 48 + 4 - 6)/12  = 46/12 = 23/6 ***
e
3 * 8 + 1  = 24 + 1 = 25 ***
f
V-100  não há resultado 

Answer 2

A(3+√64) = 3 + 8 = 11

B( 2+3√2) = 2+3√2

C(4√3-1) =  4√3-1

D(√16+√1/9-√1/4) = 4 + 1 - 1 ==> 24+8-12 ==> 20
                                       3   2              6               6

E(3*8+1) = 24+1 = 25

F(-√100) = - 10