Question

Calcule: a) (3/2)² = b) (-1/2)⁴ = c) (-1/3)³ = d) (-4/5)⁰ = e) (-5/9)¹ = f) (+7/8)¹ = g) (-1/2)⁵ = h) (-4/3)² =

Answer 1

Resposta:

a) $\frac{9}{4}$     b) $\frac{1}{16}$   c) $-\frac{1}{27}$  d) 1    e)  $-\frac{5}{9}$    f)  $\frac{7}{8}$   g)  $-\frac{1}{32}$   h)   $\frac{16}{9}$

Explicação passo-a-passo:

a) (3/2)² = $(\frac{3}{2})^{2} => (\frac{3}{2}).(\frac{3}{2})=> \frac{9}{4}$

b) (-1/2)⁴ = $(-\frac{1}{2})^{2} =>(-\frac{1}{2}).(-\frac{1}{2})(-\frac{1}{2})(-\frac{1}{2}) => \frac{1}{16}$

c) (-1/3)³ = $(-\frac{1}{3})^{3} =>(-\frac{1}{3}).(-\frac{1}{3}) .(-\frac{1}{3})=> -\frac{1}{27}$

d) (-4/5)⁰ = $(-\frac{4}{5})^{0} =>1$

e) (-5/9)¹ = $(-\frac{5}{9})^{1} =>-\frac{5}{9}$

f) (+7/8)¹ = $(\frac{7}{8})^{1} =>\frac{7}{8}$

g) (-1/2)⁵ = $(-\frac{1}{2})^{5} =>(-\frac{1}{2}).(-\frac{1}{2}) (-\frac{1}{2})(-\frac{1}{2})(-\frac{1}{2})=> -\frac{1}{32}$

h) (-4/3)² =$(-\frac{4}{3})^{2} =>(-\frac{4}{3}).(-\frac{4}{3}) => \frac{16}{9}$