Question

Calcule:
a) (-3)^-1+(-1)^-3
b) 2^-4-2^2
c) (4^-1+2^-3)^-1
d) (6^-2.3^2)^-1

Answer 1

a-)
$\frac{1}{3} + \frac{1}{1 ^{3} } = \frac{1+3}{3} = 4$
b-) $\frac{1}{2 ^{4} } - (4) = \frac{1}{16} - 4 = \frac{1-64}{16} = -63$
c-) $(\frac{1}{4} + \frac{1}{8} ) ^{-1} = \frac{4+8}{1} =12$
d-)$(\frac{1}{36} . 8 ) ^-1 = (\frac{8}{36} ) ^-1 = \frac{36}{8} = \frac{9}{2}$