Question

Calcule:
a){2 x [7 – (√16 + 1) ÷ 5] ÷ 4}² + √49 b){(-18) + [(-2) x (8-5)] ÷ (-6)}
c) 50 + 20X = 290 d) 3x + 6 = 0 e) 2x - 6 = 0 f) - 2x + 10 = - 68

Answer 1

Boa tarde,

a) {2 x [7 – (√16 + 1) ÷ 5] ÷ 4}² + √49

{2×[7-(4+1)÷5]÷4}²+√49

{2×[7-5÷5]÷4}²+√49

{2×[7-1]÷4}²+√49

{2×6÷4}²+√49

{12÷4}²+√49

{3}²+√49

9+√49

9+7

16

b){(-18) + [(-2) x (8-5)] ÷ (-6)}

{-18+[-2×3]÷(-6)}

{-18+[-6]÷(-6)}

{-18-6÷(-6)}

{-18-(-1)}

{-18+1}

-17

c)50 + 20X = 290

20x= 290 - 50

20x= 240

x= 240/20

x= 12

d) 3x + 6 = 0

3x= 0 - 6

3x= -6

x= -6/3

x= -2

e) 2x - 6 = 0

2x= 0+6

2x= 6

x= 6/2

x=3

f) - 2x + 10 = - 68

-2x= -68 -10

-2x= -78

x= -78/-2

x= 39

Espero ter ajudado!!!