calcule
A) 12 + 5 + 15 + 1 =
20 20 18 10
b) ( 3 + 1 ) + 34 - 1 =
5 4 5 10
c) (-3)⁴ + ( -1 )⁴ x ∛64 =
4 2 27
d)( -3 )² + ( 1 )⁴ x √121
4 2 81
Soluções para a tarefa
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A) 12 + 5 + 15 + 1 = mmc(20,18,10) = 180
20 20 18 10
108 + 108 + 150 + 18 ==> 216+168 ==> 384
180 180 180
b) ( 3 + 1 ) + 34 - 1 = 12+ 5 + 68-1 ==> 17 + 67
5 4 5 10 20 10 20 10
17 + 134 ==> 151
20 20
c) (-3)⁴ + ( -1 )⁴ x ∛64 = 81 + 1 x 4 ==> 81 + 4
4 2 27 4 2 3 4 6
243+8 ==> 251
12 12
d)( -3 )² + ( 1 )⁴ x √121 = 9 + 1 x 11 ==> 9 + 11
4 2 81 4 2 9 4 18
81 + 22 ==> 103
36 36
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