Question

calcule
a) √1 b) √121 c) √1,21 d) √49 e) √25 f) √144 g) ³√8 h) ⁴√16 i) ⁵√32 j) ³√1000 k) √4+√25 l) √4/√9 m) ³√27 n) √27.√4 o) √16.√25/√4 p) ⁴√10000 q) √0,49 r) √4/25 s) ⁴√81 t) √0,09​

Answer 1

a)

$\sqrt{1} = 1$

b)

$\sqrt{121} = \sqrt{ {11}^{2} } = 11$

c)

$\sqrt{1.21} = \sqrt{ \frac{121}{100} } = \sqrt{ \frac{ {11}^{2} }{ {10}^{2} } } = \frac{11}{10}$

d)

$\sqrt{49} = \sqrt{ {7}^{2} } = 7$

e)

$\sqrt{25} = \sqrt{ {5}^{2} } = 5$

f)

$\sqrt{144} = \sqrt{ {12}^{2} } = 12$

g)

$\sqrt[3]{8} = \sqrt[3]{ {2}^{3} } = 2$

h)

$\sqrt[4]{16} = \sqrt[4]{ {2}^{4} } = 2$

i)

$\sqrt[5]{32} = \sqrt[5]{ {2}^{5} } = 2$

j)

$\sqrt[3]{1 \: 000} = \sqrt[3]{ {10}^{3} } = 10$

k)

$\sqrt{4} + \sqrt{25} = \sqrt{ {2}^{2} } + \sqrt{ {5}^{2} } = 2 + 5 = 7$

l)

$\frac{ \sqrt{4} }{ \sqrt{9} } = \frac{ \sqrt{ {2}^{2} } }{ {3}^{2} } = \frac{2}{3}$

m)

$\sqrt[3]{27} = \sqrt[3]{ {3}^{3} } = 3$

n)

$\sqrt{27} \times \sqrt{4} = \sqrt{27 \times 4} = \sqrt{108} = \sqrt{ {2}^{2} \times {3}^{2} \times 3 } = 2 \times 3 \sqrt{3} = 6 \sqrt{3}$

o)

$\sqrt{16} \times \frac{ \sqrt{25} }{ \sqrt{4} } = \sqrt{ {4}^{2} } \times \frac{ \sqrt{ {5}^{2} } }{ \sqrt{ {2}^{2} } } = 4 \times \frac{5}{2} = \frac{20}{2} = 10$

p)

$\sqrt[4]{10 \: 000} = \sqrt[4]{ {10}^{4} } = 10$

q)

$\sqrt{0.49} = \sqrt{ \frac{49}{100} } = \sqrt{ \frac{ {7}^{2} }{ {10}^{2} } } = \frac{7}{10}$

r)

$\sqrt{ \frac{4}{25} } = \sqrt{ \frac{ {2}^{2} }{ {5}^{2} } } = \frac{2}{5}$

s)

$\sqrt[4]{81} = \sqrt[4]{ {3}^{4} } = 3$

t)

$\sqrt{0.09} = \sqrt{ \frac{9}{100} } = \sqrt{ \frac{ {3}^{2} }{ {10}^{2} } } = \frac{3}{10}$