Matemática, perguntado por kapoperaUwU, 8 meses atrás

Calcule:

a) 1/3 + 2/5

b) 7/2 + 2/3

c) 3/2 - 2/3

d) 4/5 - 1/2

e) 3/4 + 5/6 - 1/2


Ajudaaaaaaa TwT”

Soluções para a tarefa

Respondido por SirLouis
1

Ok , vamos lá !!

❒  Resoluções :

A )

\sf { \dfrac{1}{3}   +   \dfrac{2}{5} }

\sf {  = \dfrac{5 \times 1 + 3 \times 2}{15} }

\sf {  = \dfrac{5  + 6}{15} }

\red{\sf {  = \dfrac{11}{15} }}

B )

 \sf {\dfrac{7}{2}  +  \dfrac{2}{3} }

 \sf {=  \dfrac{3 \times 7 + 2 \times 2}{6} }

 \sf {=  \dfrac{21 + 4}{6} }

\red{ \sf {=  \dfrac{25}{6} }}

C )

\sf { \dfrac{3}{2}  -  \dfrac{2}{3} }

 \sf { = \dfrac{3 \times 3 -2 \times 2 }{6} }

 \sf { = \dfrac{9 -4 }{6} }

\red{ \sf { = \dfrac{5 }{6} }}

D )

\sf { \dfrac{4}{5}  -  \dfrac{1}{2} }

\sf {  = \dfrac{2 \times 4 - 5 \times 1}{10} }

\sf {  = \dfrac{8 - 5}{10} }

\red{\sf {  = \dfrac{3}{10} }}

E )

 \sf {\dfrac{3}{4}  +  \dfrac{5}{6}  -  \dfrac{1}{2} }

\sf {  = \dfrac{3 \times 3 + 2 \times 5 - 6 \times 1}{12} }

\sf {  = \dfrac{9 + 10- 6 }{12} }

\sf {  = \dfrac{19- 6 }{12} }

\red{\sf {  = \dfrac{13 }{12} }}

Mmc

\sf {4 , 6 , 2 |2}

\sf {2 , 3 , 1 |2}

\sf {1 , 3 , 1 |3}

\sf {1, 1 ,1}

\sf {=2 × 2 × 3}

\sf {=4× 3}

\sf {=12}

Bons estudos .

Anexos:

kapoperaUwU: Muito obrigado!❤️
SirLouis: dnd ❤
Respondido por Makaveli1996
0

Oie, Td Bom?!

a)

• MMC (3 . 5 = 15).

 \frac{1}{3}  +  \frac{2}{5}  =   \frac{5}{15} +  \frac{6}{15}  =  \frac{5 + 6}{15}  =  \frac{11}{15}

b)

• MMC (2 . 3 = 6).

 \frac{7}{2}  +  \frac{2}{3}  =  \frac{21}{6}  +  \frac{4}{6}  =  \frac{21 + 4}{6}  =  \frac{25}{6}

c)

• MMC (2 . 3 = 6).

  \frac{3}{2}  -  \frac{2}{3}  =  \frac{9}{6}   -  \frac{4}{6}  =  \frac{9 - 4}{6}  =  \frac{5}{6}

d)

• MMC (5 . 2 = 10).

 \frac{4}{5}  -  \frac{1}{2}  = \frac{8}{10}   -  \frac{5}{10}  =  \frac{8 - 5}{10}  =  \frac{3}{10}

e)

• MMC (12).

 \frac{3}{4}  +  \frac{5}{6}  -  \frac{1}{2}  =   \frac{9}{12}  +  \frac{10}{12}  -  \frac{6}{12}  =  \frac{9 + 10 - 6}{12}  =  \frac{19 - 6}{12}  =  \frac{13}{12}

Att. Makaveli1996

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