Matemática, perguntado por clara576, 1 ano atrás

calcule
a) 1-(1/3)^3÷(1/2-1)^2

b) (5- 1/2)^2÷(1/2-1)^2

c) (0,1+1/5)÷(-0,02+1/100)

d) (1/5-1/2) -(1/3-1/4)×2/5

e) -5/8+1/4×(0,2)+1/2

Soluções para a tarefa

Respondido por rodrigoreichert
5
a)
1 - (1/3)
³ ÷ (1/2 - 1)² =
1 - 1/27 ÷ (-1/2)² =
1 - 1/27 ÷ 1/4 =
1 - 1/27 * 4/1 =
1 - 4/27 =
(27 - 4) / 27 =
23 / 27

b)
(5 - 1/2)² ÷ (1/2 - 1)² =
(9/2)² ÷ (-1/2)² =
81/4 ÷ 1/4 =
81/4 * 4/1 =
81

c)
(0,1 + 1/5) ÷ (-0,02 + 1/100) =
(1/10 + 1/5) 
÷ (-2/100 + 1/100) =
3/10 ÷ (-1/100) =
3/10 * (-100/1) =
-300 / 10 =
-30

d)
(1/5 - 1/2) - (1/3 - 1/4) * 2/5 =
((2 - 5) / 10) - ((4 - 3) / 12) * 2/5 =
-3/10 - 1/12 * 2/5 =
-3/10 - 2/60 =
-3/10 - 1/30 =
(-9 - 1) / 30 =
-10 / 30 =
-1/3

e)
-5/8 + 1/4 * (0,2) + 1/2 =
-5/8 + 1/4 * 1/5 + 1/2 =
-5/8 + 1/20 + 1/2 =
(-25 + 2 + 20) / 40 =
-3 / 40
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