Question

Calcule
9 log 10 − log7^ 1 + log8^ 8

Answer 1

loga 1 = 0

loga a = 1

9log10 10 - log7 1 + log8 8

9 - 0 + 1

10

Resposta: 10

Answer 2

Explicação passo-a-passo:

Lembre-se que:

• $\sf log_{a}~a=1$

• $\sf log_{b}~1=0$

Assim:

$\sf 9\cdot log~10-log_{7}~1+log_{8}~8$

$\sf =9\cdot1-0+1$

$\sf =9-0+1$

$\sf =\red{10}$