Matemática, perguntado por Marialuiza1281, 10 meses atrás

Calcule:
7-²
(5/7)-²
(2/3)-⁴
5-³
(2/5)-³
(6/3)-¹


Soluções para a tarefa

Respondido por ibferretto
2

Resposta:

Explicação passo-a-passo:

7^{-2} =(\frac{1}{7} )^{2} = \frac{1*1}{7*7} =\frac{1}{49}=0,0204...\\\\(\frac{5}{7})^{-2}=(\frac{7}{5})^{2}=\frac{7*7}{5*5}=\frac{49}{25}=1,96\\\\(\frac{2}{3})^{-4}=(\frac{3}{2})^{4}=\frac{3*3*3*3}{2*2*2*2}=\frac{81}{16}=5,06\\\\5^{-3}=(\frac{1}{5})^{3}=\frac{1*1*1}{5*5*5}=\frac{1}{125}=0,008\\\\(\frac{2}{5})^{-3}=(\frac{5}{2})^{3}=\frac{5*5*5}{2*2*2}=\frac{125}{8}=15,625\\\\\frac{6}{3}^{-1}=(\frac{3}{6})^{1}=\frac{3}{6}=0,5

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