Question

calcule:

(6x²+7xy-8)-(-4x²+5xy+3)


(4x+2).(x-3) ​

Answer 1

1.

$= (6x {}^{2} + 7xy - 8) - ( - 4x {}^{2} + 5xy + 3)$

$= 6x {}^{2} + 7xy - 8 + 4x {}^{2} - 5xy - 3$

$= (6 + 4)x {}^{2} + (7 - 5)xy - 8 - 3$

$\boxed{ = 10x {}^{2} + 2xy - 11 }$

2.

$= (4x + 2) \: . \: (x - 3)$

$= 4x \: . \: (x - 3) + 2(x - 3)$

$= 4x {}^{2} - 12x + 2x - 6$

$\boxed{ = 4x {}^{2} - 10x - 6 }$

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