Question

Calcule………………………………..

Answer 1

Resposta:

Olá bom dia!

a)

$\frac{21x^8}{7x^3} = \frac{21}{7} \frac{x^8}{x^3} = 3x^{8-3} = 3x^5$

b)

$\frac{14a^6b^4c^3}{2a^2b^3c} = \frac{14}{2} \frac{14a^6b^4c^3}{2a^2b^3c} = 7a^4bc^2$

c)

$\frac{8a^5b^4c + 16a^3b}{4a^2b} = \frac{8a^5b^4c }{4a^2b}+ \frac{+ 16a^3b}{4a^2b} \\\\= 2a^3b^3 c + 4a^2$